Calculate the no. of iron atoms present in one molecule of haemoglobin given that haemoglobin contains 0.33% of iron by weight. the molecular weight of it is approx. 67200. options : (1) 1 (2) 2 (3) 4 (4) 6

Percentage of iron present in Haemoglobin = 0.33%

Molecular weight = 67200

Weight of iron = 0.33/100*67200

=221.76

The atomic weight of iron = 55.845

therefore the no of moles of iron = 221.76/55.845

= 3.97 = approx 4

The answer is 4