Percentage of iron present in Haemoglobin = 0.33%
Molecular weight = 67200
Weight of iron = 0.33/100*67200
=221.76
The atomic weight of iron = 55.845
therefore the no of moles of iron = 221.76/55.845
= 3.97 = approx 4
The answer is 4
Percentage of iron present in Haemoglobin = 0.33%
Molecular weight = 67200
Weight of iron = 0.33/100*67200
=221.76
The atomic weight of iron = 55.845
therefore the no of moles of iron = 221.76/55.845
= 3.97 = approx 4
The answer is 4
BOOK
Free Class
BOOK
Free Class