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Question

Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.


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Solution

  • The chemical formula of Aluminium oxide is Al2O3.

1moleofAl2O3=2×27+3×16=102gMolesofAl2O3=0.051102=5×10-4moles1mole=6.02×1023molecules5×10-4gofAl2O3=5×10-4×6.02×1023=3.011×1020molecules

Number of Al3+ ions in 1 molecule of Al2O3 is 2.

Thus, the number of Aluminium ions in 0.051 g of Al2O3 will be,

2×3.011×1020=6.022×1020


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