Calculate the number of atoms in each of the following
(i) $52molesofAr$
(ii) $52uofHe$
(iii) $52gofHe$

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Solution

The weight of a sample, its atomic mass from the periodic table, and a constant called Avogadro's number are required to determine the number of atoms in a formula
Number of atoms in $52molesofAr$ ,
$1 m o l e o f Ar {=6.022\times10}^{23} a t o m s o f Ar 52 m o l e s o f Ar = 52 \times 6.022 \times 10^{23} ∴ 52 m o l e s o f Ar = 3.13144 \times 10^{25} a t o m s o f Ar$
Number of atoms in $52uofHe$ ,
$A t o m i c m a s s o f He = 4 a m u 52 u o f He = 52 / 4 = 13 a t o m s$
Number of atoms in $52gofHe$ ,
$1 m o l e o f He = 4 g = 6.022 \times 10^{23} a t o m s o f He 52 g o f He = 52 / 4 = 13 m o l e s N u m b e r o f a t o m s i n 13 m o l e s o f He = 13 \times 6.022 \times 10^{23} a t o m s N u m b e r o f a t o m s i n 13 m o l e s o f He = 78.29 \times 10^{23} a t o m s 52 g o f He = 7.829 \times 10^{24} a t o m s o f He$

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