# Calculate The Number Of Iron Atoms In A Piece Of Iron Weighing 2.8. G. (Atomic Mass Of Iron = 56)

Given:

Weight of iron (Fe) = 2.8 g

The atomic mass of iron (Fe) = 56

Moles Of Iron = $$\frac{Weight Of Iron}{Atomic Mass Of Iron}$$ $$\Rightarrow \frac{2.8}{56}$$ $$\Rightarrow 0.05 moles.$$

One mole = 6.022 * 1023 atoms.

0.05 moles = 6.022 * 0.05 * 1023 atoms.

$$\Rightarrow$$ 3.0115 * 1022 atoms.

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