Calculate The Percentage Composition Of Nitrogen In Urea .

The molecular weight of Urea [CO(NH₂)₂].

= 1 * 12 + 1 * 16 + 2 * 14 + 4 * 1

= 12 + 16 + 28 + 4

= 60 g

60g of urea contains 28g of Nitrogen

Therefore, the percentage of Nitrogen =$$\frac{28}{60} * 100$$

= 46.6 %

The percentage composition of Nitrogen in Urea is 46.6% N

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