Question

Carry out the following division: $-36{\mathrm{y}}^3÷9{\mathrm{y}}^2$

Answer 1

Given: $-36{\mathrm{y}}^3÷9{\mathrm{y}}^2$

$\begin{array}{rcl}\frac{-36{\mathrm{y}}^3}{9{\mathrm{y}}^2}& =& \frac{-36}{9}\times \frac{{\mathrm{y}}^3}{{\mathrm{y}}^2}\\ & =& -4\times {\mathrm{y}}^{3-2}\left[\mathrm{Note}:\frac{{\mathrm{a}}^{\mathrm{m}}}{{\mathrm{a}}^{\mathrm{n}}}={\mathrm{a}}^{\mathrm{m}-\mathrm{n}}\right]\\ & =& -4{\mathrm{y}}^1\\ & =& -4\mathrm{y}\end{array}$

Hence, $-36{\mathrm{y}}^3÷9{\mathrm{y}}^2=-4\mathrm{y}$