Question

${\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{Br}\stackrel{\mathrm{Mg},\mathrm{dry}\mathrm{ether}}{\to }\mathrm{A}\stackrel{{\mathrm{H}}_2\mathrm{O}}{\to }\mathrm{B}$ Identified A and B compound.

Answer 1

This reaction is basically the reaction of the formation of the Grignard reagent and then the Hydration of the reagent to form ethane.

The complete reaction is as follows:

$$\begin{gathered} {\mathrm{CH}}_3-{\mathrm{CH}}_2-\mathrm{Br}\stackrel{\mathrm{Mg},\mathrm{dry}\mathrm{ether}}{\to }{\mathrm{CH}}_3-{\mathrm{CH}}_2\mathrm{Mg}\mathrm{Br}\stackrel{{\mathrm{H}}_2\mathrm{o}}{\to }{\mathrm{CH}}_3-{\mathrm{CH}}_3+\mathrm{Mg}\left(\mathrm{OH}\right)\mathrm{Br} \\ \mathrm{Ethylbromide}\mathrm{ethylmagnisium}\mathrm{bromide}\mathrm{ethane} \\ (\mathrm{Grignard}\mathrm{reagent}) \end{gathered}$$

So,

A= ethyl magnesium bromide which is also called a Grignard reagent.

B= Ethane.