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Catalytic Hydrogenation

CH3COCl+H2 in...

Question

CH₃COCl + H₂ in presence of Pd and BaSO₄ the product is -

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Solution

Acetyl chloride in presence of BaSO₄gets reduced into alcohol but if we use Pd(Palladium) with barium sulphate it will act as a poison and acetyl chloride will be reduced only up to aldehyde only.
${CH}_{3} COCl + H_{2} \overset{{BaSO}_{4} / Pd}{\to} {CH}_{3} CHO$
Some of the reducing agents are as follows:
Sodium borohydride (NaBH₄)
Lithium aluminium hydride (LiAlH₄)
Diisobutyl aluminium hydride (DIBAlH)

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CH3COCl+H2------->CH3CH2OH------->CH3CHO(in presence of pd,BaSO4 and quinoline).

Here quinoline acts as what?

a)+ve catalyst

b)catalyst poison

c)promoter

d)medium

Q. Reduction of acetyl chloride with

H_{2}

in presence of Pd and

B a S O_{4}

Q. The reduction of 4-octyne with

H_{2}

in the presence of

P d / B a S O_{4}

and quinoline gives :

Q. The solubility product of

B a {S O}_{4}

4 \times 10^{- 10}

. The solubility of

B a {S O}_{4}

0.02 N

H_{2} {S O}_{4}

Q. The reduction of 4-octyne with

H_{2}

in the presence of

P d / B a S O_{4}

and quinoline gives:

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