# Check The Correctness Of The Equation Fmv2R Where F Is A Force, M Is Mass, V Is Velocity And R Is A Radius.

Given force F =$$\frac{mv^{2}}{r}$$

As we know, Force = mass×acceleration F = m * a

Now by both the formulas dimensionally, we get

$$ma = \frac{mv^{2}}{r}$$ $$MLT^{-2} = ML^{2}T^{-2}L^{-1}$$ $$MLT^{-2} = MLT^{-2}$$

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