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Question

Compute the heat generated while transferring 96000coulombs of charge in 1hour through a potential difference of 50V.


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Solution

Step 1: Given information

Charge, Q=96000C

Time, t=1hr=60×60=3600s

Potential difference, V=50V

Step 2: Finding the current

We know the formula,

Current,

I=Qt

By substituting the values, we get

=960003600=803A

Step 3: Finding the heat generated

The quantity of heat generated will be:

H=V×I×t

By substituting the values,

=50×803×3600=4.8×106J

Therefore, the heat generated is 4.8×106J.


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