Compute The Median From The Following Data : Marks Obtained - 0 7, 7-14,14-21,21-28,28-35,35-42,42-49. Number Of Students 3,4,7,11,0,16,9

Given:

Marks Obtained

0 – 7

7 – 14

14 – 21

21 – 28

28 – 35

35 – 42

42 – 49

Number Of Students

3

4

7

11

0

16

9

Sol:

Marks Obtained

Number Of Students

Cumulative Frequency

0 – 7

3

3

7 – 14

4

7

14 – 21

7

14

21 – 28

11

25

28 – 35

0

25

35 – 42

16

41

42 – 49

9

50

N =\( \sum f = 50 \) \( \frac{N}{2} = \frac{50}{2} = 25 \)

The cumulative frequency is greater than the 25 is 41 and the corresponding class is 35 – 42

The median class is 35 – 42

Median =\( l + (\frac{\frac{N}{2} – cf}{f}) * h \)

Here

l is the lower limit of the median class=35

\( \frac{N}{2} = 25 \)

cf is the cumulative frequency = 25

h = The class size = 7

f = frequency of the median class=16

Median = \( 35 + (\frac{25 – 25}{16}) * 7 \)

Median = 35 + 0

Median = 35

Therefore, the median for the given data is 35

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