Compute the number of ions present in 5.85 g of sodium chloride.

Answer: 1.2042 ×1023 ions

The molar mass of NaCl = The atomic weight of sodium(Na) + The atomic weight of Chlorine(Cl)

  • The atomic weight of Na = 22.99 g
  • The atomic weight of Cl = 35.45 g

Thus, molar mass of NaCl = 23 + 35.5 = 58.5g/mole.

Number of moles = Given mass/Molar mass

Number of moles = 5.85/58.5

Number of moles = 0.1 mole

Each NaCl particle contains one Na+ and one Cl ion, total of 2 ions

Total moles of ions = 0.1 × 2 = 0.2 moles

Number of ions = total number of moles of ions X Avogadro’s number

Number of ions = 0.2 × 6.022 ×1023

Number of ions = 1.2042 ×1023 ions

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