Answer: (3)
Molarity of H2SO4 solution = number of moles of the solute/Volume of solution given in terms of litres
Molarity of H2SO4 solution =
\(\begin{array}{l}\frac{98\times 10 00}{98 \times 100}\times 1.802\end{array} \)
Molarity of H2SO4 solution (M1) = 18.02
Let us consider V1 volume of H2SO4 is used to prepare 1 litre of 0.1M of H2SO4.
Using formula
M1V1 = M2V2
V1 = M2V2/M1
V1 = 1000 × 0.1 / 18.02
V1 = 5.55ml
5.55ml acid = 9.8g = 0.1 Molar acid
Refer more
- What are molarity, molality, and normality? Explain with example
- Differentiate between molarity and molality of a solution. How can we change the molality value of a solution into molarity value
- Find molarity, molality, normality and normality of h2so4 in 98% w/w solution. (p=1.8g/ml).
- Calculate the amount of oxalic acid used to prepare 100 ml of 0.1n and 0.1m solution
