$$N_{2} + 3H_{2} ⇌ 2NH_{3} —[1]$$ $$K1 = \frac{[NH_{3}]^{2}}{[N_{2}][H_{2}]^{3}}$$

Reversing the equation [1], we get:

;$$\frac{1}{K1} = \frac{[N_{2}][H_{2}]}{[NH_{3}]^{2}}—[2]$$ $$N_{2} + O_{2} ⇌ 2 N O —[3]$$ $$K2 = \frac{[NO]^{2}}{[N_{2}][O_{2}]}—[4]$$ $$N_{2} + 1/2 O_{2} ⇌ H_{2}O—[5]$$

Now by multiplying equation [5] by [3], we get:

$$3H_{2} + 3/2 O_{2} ⇌ 3 H_{2} O$$

Therefore, $$K_{3}^{3} = \frac{[H_{2}O]^{3}}{[H_{2}]^{3}[O_{2}]^{3/2}}—[6]$$ $$2NH_{3} + 5/2 O_{2} ⇌ 2NO + 3 H_{2} O$$ $$K = \frac{[NO]^{2}[H_{2}O]^{3}}{[NH_{3}^{2}][O_{2}]}$$

Therefore, from the equations [2] [4] and [6], we get

$$K = K = \frac{k_{2} * k_{3}^{3}}{k_{1}}$$

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