1. Draw a line segment AB which is equal to XY+YZ+ZX = 11 cm.
2. Make an angle ∠Y = 30° from point A and the angle be∠LAB
3. Make an angle ∠Z = 90° from the point B and the angle be ∠MAB
4. Bisect ∠LAB and ∠MAB at point X.
5 Considering the perpendicular bisector of the line XA and XB and the intersection point be Y and Z, respectively.
6. Join XY and XZ
7.Hence, XYZ is the required triangle