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Question

Construct a triangle XYZ in which Y=30°, Z=90° and XY+YZ+ZX=11cm.


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Solution

Construct a triangle XYZ:

Draw a line segment AB which is equal to XY+YZ+ZX=11cm.

Make an angle Y=30° from point A and let the angle beLAB.

Make an angle Z=90° from the point B and the angle be MBA.

Bisect LAB and MBA at point X.

Construct the perpendicular bisector of the line XA and XB and let the intersection point on AB be Y and Z, respectively.

Join XY and XZ.

Hence, XYZ is the required triangle


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