The steps for construction are given below:
1. Draw a line segment AB = 5.8 cm.
2. From point A, draw a ray P to making an angle of 60o i.e. ∠PAB = 60o.
3. From point B, draw a ray Q to making an angle of 30o i.e. ∠QBA = 30o.
4. Now the two rays AP and BQ intersect From the point C.
Then, ΔABC obtained is the required triangle.