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Question

Construct DEF such that DE=5cm, DF=3cm and mEDF=90°.


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Solution

The steps for construction are given below:

Step 1: Draw a line segment DF=3cm.

Step 2: At point D, draw a ray to make an angle of 90°.

Step 3: Taking D as center, 5cm as radius, draw an arc on the ray. Let the point where the arc intersects the ray be E.

Step 4: Join EF.

Hence, DEF obtained is the required right angled triangle.


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