Convert ethyl bromide into ethane.

Ethyl bromide in the presence of an aqueous solution of KOH will give ethanol as a product and KBr as a side product. Now, reduction of a hydroxyl group(-OH) using lithium aluminum hydride will produce ethane C2H6.

CH₃-CH₂-Br + aq. KOH—->CH₃-CH₂-OH + KBr

Was this answer helpful?


0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *




Free Class