Copper forms two chlorides CuCl and CuCl2 (1) Identify the copper ions in these compounds? (2) What is the valency of copper in each of these compounds? (3) By writing the sub-shell electronic configuration of copper, find out a sub-shells from which the electrons are lost to form these ions. (4) Write the period and group to which copper belongs. (Hint: Atomic number of copper =29)

Answer:

Given

Copper forms two chlorides CuCl and

Atomic number of copper (Cu) = 29.CuCl2

(1) The copper ions in the CuCl and CuCl2 compounds are

CuCl − Cu+
CuCl2− Cu2+

(2) The valance of copper in

CuCl is 1

CuCl2is 2.

(3) Electronic configuration

Cu (29)− 1s22s22p63s23p63d104s1.

In the case of CuCl electron is lost from 4s orbital.

In the case of CuCl2 electron is lost from 4s orbital and another electron is lost from 3d orbital.

The electronic configuration of Cu2+ is 1s22s22p63s23p63d9

(4) Copper (Cu) belongs to 4th period and 11th group in the periodic table.

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