CosA/1+sinA+1+sinA/cosA = 2secA

Given cosA/(1+sinA) +(1+sinA)/cosA

On taking the LCM we get,

={cos²A +(1+sinA)²}/cosA.(1+sinA)

Combining the like terms and adding and also we know that,use sin²A+cos²A =1

=(1+1+2sinA)/cosA(1+sinA)

=2(1+sinA)/cosA(1+sinA)

=2/cosA

=2secA

Hence Proved

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