Eight dipoles of equal magnitude are placed inside a cube. The total electric flux coming out of the cube will be _____.
- \(\frac{8e}{\varepsilon _0}\)
- \(\frac{e}{\varepsilon _0}\)
- \(\frac{16e}{\varepsilon _0}\)
- 0
Answer: The total electric flux coming out of the cube will be zero.
Explanation: The electric flux given by the total charge enclosed by the surface multiplied by 1/ε0.
The net charge of the dipole is zero because it consists of two equal and opposite charge. Hence, the net charge of the eight dipoles enclosed inside a cube is zero. Therefore, the total electric flux coming out of the cube will be zero.
