Equal weights of ethane and hydrogen are mixed in an empty container at 25�c. the fraction of the total pressure exerted by hydrogen is a. 1 : 2 b. 1 : 1 c. 1 : 16 d. 15 : 16

Let x g of each gas is mixed.

Mole of ethane = x/30

Mole of hydrogen = x/2

Mole fraction of hydrogen = (x/2)/(x/2 + x/30)

= 15/16 ⇒ (Partical pressure of H_2)/(Total pressure)

= mole fraction of hydrogen = 15 : 16

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