CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Estimate the volume occupied by one molecule of water (density=1gcm-3)


Open in App
Solution

Step 1: Find the mass of one Water (H2O) molecule.

We know that, 1mole=6.023×1023molecules

So, 18g=6.02×1023molecules, as the mass of one Water molecule is 18gmol-1

18g=massof6.02×1023watermolecules

Mass of one water molecule=186.023×1023

Step 2: Find the density of one water molecule

It is given that density=1gcm-3

We know that:

Volume=MassofonewatermoleculeDensityofonewatermolecule

Volume=186.023×1023×1cm33.0x10-23cm3

Hence, the volume occupied by one molecule of water is 3.0×10-23cm3


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mixtures
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon