Question

Evaluate: $\sin \frac{2\mathrm{\pi }}{3}$

Answer 1

The radian measure of $\mathrm{\pi }$ is ${180}^0$

So $\frac{2\mathrm{\pi }}{3}$$=$$\frac{2\times {180}^0}{3}$

$=$$2\times {60}^0$

$=$${120}^0$

⇒$\sin \frac{2\mathrm{\pi }}{3}$$=$$\sin {120}^0$

$=$$\sin ({90}^0+{30}^0)$

$=$$\cos {30}^0$

$=$$\frac{\surd 3}{2}$

Thus, the required value of $\sin \frac{2\mathrm{\pi }}{3}$$=$$\frac{\surd 3}{2}$.