Evaluate $\sin 330 °$

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Solution

To evaluate : $\sin 330 °$
We can write $330^{0}$ as $330^{0} = 360^{0} - 30^{0}$ .
So $\sin 330 °$ $= \sin (360^{0} - 30^{0})$ (Identity used : $\sin (360^{0} - θ) = - sinθ$ )
$= - \sin 30^{0}$
$= - \frac{1}{2}$ ( The value of $\sin 30^{0} = \frac{1}{2}$ )
Thus, the required value of $\sin 330 °$ $= - \frac{1}{2}$

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