Evaluate the freezing point of BaCl2 if equimolar solution of NaCl and BaCl2 are prepared in water. Also mentioned that freezing point of NaCl was found to be -2C.

We know that, For NaCl i = 2 For BaCl2 = 3 ∆TF (NaCl) / ∆TF (BaCl2 ) = 2 / 3 Hence, ∆TF (BaCl2 ) = 3 x 2 / 2 = 3 TF = – 3◦C