Expand this: (3x+4y)(3x+5y)

Solution:

(3x+4y)(3x+5y) = 3x(3x+5y) + 4y(3x+5y) 

= 9x2 + 15xy + 12xy + 20y2

= 9x2 + 27xy + 20y2

Hence (3x+4y)(3x+5y) = 9x2 + 27xy + 20y2

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