Expand this: $(3 x + 4 y) (3 x + 5 y)$ .

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Solution

Given: $(3 x + 4 y) (3 x + 5 y)$
$(3 x + 4 y) (3 x + 5 y) = 3 x (3 x + 5 y) + 4 y (3 x + 5 y)$
$= 9 x^{2} + 15 x y + 12 x y + 20 y^{2}$
$= 9 x^{2} + 27 x y + 20 y^{2}$
$H e n c e (3 x + 4 y) (3 x + 5 y) = 9 x^{2} + 27 x y + 20 y^{2}$

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