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Question

Explain Ostwald's dilution law.


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Solution

Step 1: Concept of Ostwald's dilution law

  1. Ostwald's dilution law describes the dissociation constant of the weak electrolyte with the degree of dissociation α and the concentration of the weak electrolyte.
  2. It is applicable only for weak electrolyte such as Acetic acid (CH3COOH)

Step 2: Derivation of Ostwald's dilution law

  1. Consider a binary electrolyte AB which dissociates into A+ and B- ions, AB(l)A+(l)+B-(l).
  2. At t=0 when no reaction is going on Concentration of AB= C and Concentration of A+ and B- ions= 0 since there is no product formed.
  3. At equilibrium Concentration of AB= C-, Concentration of A+and B- ions=
  4. AB(l)A+(l)+B-(l) putting the values of an reactants and products concentration the equilibrium constant can be written as: K=[A+(l)][B+(l)][AB(l)] which is also written as: K=[][]C-=()2C(1-α)
  5. For very weak electrolytes since α<<<1,(1-α)1 therefore the expression of equilibrium constant can be written as: K=2 then α=KC where K= dissociation constant of weak acid, α= degree of dissociation, C= concentration.
  6. Ostwald's dilution law states that only at infinite dilution the weak electrolyte undergoes complete ionization.

Therefore, Ostwald's dilution law relates dissociation constant with degree of dissociation and concentration.


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