d2y/dx2 is defined as d2y/dx2 = d/dx (dy/dx)
Let function f(x) be y = x^3 + 20x^2
To find: d2y/dx2
first find dy/dx
So, dy/dx = 3x^2 + 40x
For d2y/dx2 differentiate the dy/dx again
d2y/dx2 = d/dx ( 3x^2 + 40x)
= 6x +40
d2y/dx2 is defined as d2y/dx2 = d/dx (dy/dx)
Let function f(x) be y = x^3 + 20x^2
To find: d2y/dx2
first find dy/dx
So, dy/dx = 3x^2 + 40x
For d2y/dx2 differentiate the dy/dx again
d2y/dx2 = d/dx ( 3x^2 + 40x)
= 6x +40
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