Explain the procedure to find (d2y/dx2) [second order derivative] of any function y=f(x).

d2y/dx2 is defined as d2y/dx2 = d/dx (dy/dx)

Let function f(x) be y = x^3 + 20x^2

To find: d2y/dx2

first find dy/dx

So, dy/dx = 3x^2 + 40x

For d2y/dx2 differentiate the dy/dx again

d2y/dx2 = d/dx ( 3x^2 + 40x)

= 6x +40