Factorise: 2x3+54y3-4x-12y
Factorization
The given equation is,
2x3+54y3-4x-12y=2(x3+27y3-2x-6y)
=2{(x3+27y3)–2(x+3y)}
We know the identity
a3+b3=(a+b)(a2–ab+b2)
∴2x3+54y3-4x-12y=2{(x+3y)(x2-3xy+9y2)-2(x+3y)}
=2(x+3y)(x2-3xy+9y2-2)
Hence, the result of the factorization of the given expression is 2(x+3y)(x2-3xy+9y2-2).
Factorise:
2x3+54y3−4x−12y
4(2x−3y)2−8x+12y−3