x3 + x – 3x2 – 3
Here x is common factor in x3 + x and – 3 is common factor in – 3x2 3×2 – 3
x3 – 3x2 + x – 3
x2 (x – 3) + 1(x – 3)
Taking ( x – 3) common
(x – 3) (x2 + 1)
Therefore x3 + x – 3x2 – 3 = (x – 3) (x2 + 1)
x3 + x – 3x2 – 3
Here x is common factor in x3 + x and – 3 is common factor in – 3x2 3×2 – 3
x3 – 3x2 + x – 3
x2 (x – 3) + 1(x – 3)
Taking ( x – 3) common
(x – 3) (x2 + 1)
Therefore x3 + x – 3x2 – 3 = (x – 3) (x2 + 1)
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