Factorize 6ab - b-2 - 12ac - 2bc - Maths Q-A

Factorize the given polynomial6ab b^2+12ac 2bc0ex0ex=6ab+12ac b^2 2bc0ex0ex=6a(b+2c) b(b+2c)0ex0ex=(6a b)(b+2c)Hence the factorized form of the polynomial 6ab b ...

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Byju's Answer

Standard VIII

Mathematics

Factorizing a Term

Factorize 6ab...

Question

Factorize: $6 a b - b^{2} + 12 a c - 2 b c$

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Solution

Factorize the given polynomial
$6 a b - b^{2} + 12 a c - 2 b c = 6 a b + 12 a c - b^{2} - 2 b c = 6 a (b + 2 c) - b (b + 2 c) = (6 a - b) (b + 2 c)$
Hence the factorized form of the polynomial $6 a b - b^{2} + 12 a c - 2 b c$ is $(6 a - b) (b + 2 c)$ .

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Factorize: 6ab-b2+12ac-2bc

Factorize the given polynomial6ab-b2+12ac-2bc=6ab+12ac-b2-2bc=6a(b+2c)-b(b+2c)=(6a-b)(b+2c)Hence the factorized form of the polynomial 6ab-b2+12ac-2bc is (6a-b)(b+2c).

Factorize: $6 a b - b^{2} + 12 a c - 2 b c$

Factorize the given polynomial
$6 a b - b^{2} + 12 a c - 2 b c = 6 a b + 12 a c - b^{2} - 2 b c = 6 a (b + 2 c) - b (b + 2 c) = (6 a - b) (b + 2 c)$
Hence the factorized form of the polynomial $6 a b - b^{2} + 12 a c - 2 b c$ is $(6 a - b) (b + 2 c)$ .