Find 3 consecutive even numbers such that the sum of the first and the last numbers exceed the second number by 10

Let the three consecutive even numbers be X , X+2 and X+4

As per the given statement

X + X+4 =X+2 + 10

2X +4 = X + 12

X = 8

So first number is 8

Second number = X+2 = 8 +2 = 10

Third number = X + 4= 8+4 = 12

The three consecutive numbers are 8,10 and 12.

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