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Question

Find 3 consecutive even numbers such that the sum of the first and the last numbers exceed the second number by 10.


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Solution

Step 1: Define even numbers and suppose three consecutive even numbers

About Even Numbers:

  1. The numbers which are completely divided by 2 are called even numbers.
  2. The difference between any two consecutive even numbers is always 2.

Let, the three consecutive even numbers are as follows,

The first number =x …(i)

The second number =x+2 …(ii)

The third number =x+4 …(iii)

Step 2: Form an equation based on the given condition and simplify it for x

According to the question,

firstnumber+thirdnumber=secondnumber+10x+x+4=x+2+10x+x+4=x+2+102x+4=x+122x-x=12-4x=8

Step 3: Substitute the value of x in equations (i), (ii) and (iii)

So, the first number =x

the first number =8

And, the second number =x+2

the second number =8+2

the second number =10

Also, the third number =x+4

the third number =8+4

the third number =12

Hence, the three required consecutive even numbers are 8,10 and 12.


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