Amount of oxygen required to burn 14 grams of C2H4
Following is the reaction of the burning of C2H4 in presence of oxygen.
C2H4 + 3O2 → 2CO2 + 2H2O
So we can say that to burn 26 grams of C2H4, 96 grams of oxygen is required.
Therefore, to burn 14 grams of C2H4, we need the following amount of oxygen:
(96/26)×14 = 51.7
Therefore, 51.7 grams of oxygen is required to burn 14 grams of C2H4 (that is ethene).