Find out the molarity of 30 g of CO(NO3)2.6H2O in 4.3 L of solution

Given,

Weight of CO(NO3)2.6H2O = 30 g

Volume of solution = 4.3 L

 we know that molar mass of Co(NO3)2.6H2O = 291 g / mol

Molarity = Number of moles / Volume of solution

Hence, the number of moles of solute = given weight/molar mass = 30/291= 0.103 mol

Molarity = 0.103/ 4.3 = 0.023M

Therefore, molarity of 30 g of CO(NO3)2.6H2O in 4.3 L of solution is 0.023M

BOOK

Free Class