Distance d between two parallel lines y = mx + c1 and y = mx + c2 is given by
d = |C1–C2|/√A2 + B2
d1= distance of perpendicular from (0,0) to 3x+4y+7 = 0
Using formula, we get
d1= (3 × 0 + 4 × 0 + 7) /√(32+42) = 7/5
d2 = (3 × 0 + 4 × 0 + (−5) )/ √(32+42) = −5/5
Required distance is =|d1 − d2| = ∣7/5 − (−5/5)∣ = 12/5
