The length of the chord = 16cm
The radius of the circle = 10cm
When a perpendicular is drawn on the chord such that the chord is bisecting into two. Then the length of the chord will be halved, that is it becomes 8cm.
Using the Pythagorean theorem,
OA^2 = OC^2 + AC^2
10^2 = OC^2 + 8^2
100 = OC^2 + 64
OC^2 = 36
OC = 6cm
Therefore, the distance of the chord from the centre of the circle is 6cm.
