Question

Find the greatest number of $6$ digits which is a perfect square. Find the square root of this number.

Answer 1

Find the greatest $6$-digit which is a perfect square

First, $7$digit number is $1000000$ which is square of $1000$

So, the perfect square number should be less than $1000000$ and square root should be less than$1000$.

Then, the number just smaller than$1000$ is $999$.

$\therefore$,square of $999=998001$

Hence, a greatest $6$-digit number which is perfect square is $998001$and its square root is $999$.