Put tan^-1[x] = y
or x=tany
or dx=sec^2ydy
Now integral becomes
0 to tan^(-1)(102) [y]sec^ydy
Split this integral as 0 to 1 + 1 to tan^(-1)(102)
from 0 to 1 [y]=0
from 1 to tan^(-1)(102), [y]=1
Hence, answer is 102-tan1
Put tan^-1[x] = y
or x=tany
or dx=sec^2ydy
Now integral becomes
0 to tan^(-1)(102) [y]sec^ydy
Split this integral as 0 to 1 + 1 to tan^(-1)(102)
from 0 to 1 [y]=0
from 1 to tan^(-1)(102), [y]=1
Hence, answer is 102-tan1
BOOK
Free Class
BOOK
Free Class