Find the number of terms in an arithmetic progression with the first term 2 and the last term is 62, given that the common difference is 2.

Tn = a + (n – 1) d
Tn = 62
d = 2
a = 2
62 = 2 + (n – 1) 2
60 = (n – 1) 2
30 = (n – 1)
n = 31 terms

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