Question

Find the odd one out from the following:

• A. $9$
• B. $16$
• C. $64$
• D. $100$

Answer 1

The correct option is C

$64$

Evaluate the odd one out:

The given numbers are,

$9,16,64,100$

Here we can observe that three of these four numbers are perfect squares but one of them is a perfect cube.

$\therefore$For $9$ we get, $9=3^2$

For $16$ we get, $16=4^2$

For $100$ we get, $100={10}^2$

But, for $64$ we can see that $64=4^3$.

Therefore, $64$ is the odd one in this series and hence option $\left(\mathrm{C}\right)$ is the correct answer.