 # Find the oxidation number of Cr in K2Cr2O7 ?

Potassium dichromate is an ionic compound consisting of two potassium cations and one dichromate anion. The coordination geometries around the chromium atoms are tetrahedral.

## We need to find the oxidation number of Cr in K2Cr2O7

Potassium exhibits an oxidation state of +1, oxygen exhibits an oxidation state of -2

So, the total charge of potassium ions is +1(2)=+2, while oxygen ions is −2(7)=−14.

Let x be the oxidation number of two chromiums.

Hence we can write the equation as

2+x−14=0

−12+x=0

x=12

So, two chromium atoms have an oxidation number of +12.

So one chromium atom will have an oxidation number of +12 /2=+6.

So oxidation number of Cr in K2Cr2O7 is +6.

Hence in the molecule potassium exhibits an oxidation state of +1, oxygen exhibits an oxidation state of -2 and chromium exhibits an oxidation state of +6

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