Find the oxidation number of Cr in K2Cr2O7 ?

Potassium dichromate is an ionic compound consisting of two potassium cations and one dichromate anion. The coordination geometries around the chromium atoms are tetrahedral.

We need to find the oxidation number of Cr in K2Cr2O7

Potassium exhibits an oxidation state of +1, oxygen exhibits an oxidation state of -2

So, the total charge of potassium ions is +1(2)=+2, while oxygen ions is −2(7)=−14.

Let x be the oxidation number of two chromiums.

Hence we can write the equation as

2+x−14=0

−12+x=0

x=12

So, two chromium atoms have an oxidation number of +12.

So one chromium atom will have an oxidation number of +12 /2=+6.

So oxidation number of Cr in K2Cr2O7 is +6.

Hence in the molecule potassium exhibits an oxidation state of +1, oxygen exhibits an oxidation state of -2 and chromium exhibits an oxidation state of +6

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