Find the value of i^-1?

We have to find the value of i-1

Solution

i-1 can be expressed as 1/i

Now multiplying Numerator and denominator by i we get

\(\frac{1}{i} X \frac{i}{i}\) \(\frac{i}{i^{2}}\)

We know that i2 = -1

Substituting i2 = -1 in above equation we get

\(\frac{i}{-1}\)

= -i

Answer

The value of i-1 = -i

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