Find the value of k for which the quadratic equation kx2 - 14x +8=0

Answer:

Consider a given quadriatric equation kx2 – 14x + 8 = 0

kx2 – 14x + 8 = 0

L<et us consider the value of x be 2, substitute in the equation we get

k(22) – 14×2 + 8 = 0

4k – 28 +8 = 0

4k -20 = 0

4k = 20

k = 20/4

k = 5

Let us check the equation by putting the value of k in the given quadriatric equation where k = 5 and x = 2

5× 22 – 14×2 + 8 = 0

20 – 28 + 8 = 0

20 – 20 = 0

0 = 0

LHS = RHS

∴ Value of k = 5

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