Find the value of k such that the polynomial x�-(k+6) X+2(2k-1) has sum of its zeroes equal to half of their product

Sum of zero = (-b)/a

= -(-(k+6))


Product of zero


= 2(2k-1) =4k-2

It is given in question

Sum of zero = 1/2 of product

K+6 = 1/2(4k-2

k+6 = 2k -1

6+1 = 2k-k

7 = k

Therefore k = 7

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