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Question

Find the value of tan1tan2tan3.......tan89.


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Solution

Find the value of the given expression.

Given: tan1tan2tan3.......tan89.

By solving the given expression we get,

tan1tan2tan3.......tan89=tan1tan89tan2tan88......tan44tan46tan45=tan1tan90-1tan2tan90-2.......tan44tan90-44tan45=tan1cot1tan2cot2.......tan44cot44tan45[tan(90-θ)=cotθ]=tan1×1tan1tan2×1×tan2.......tan44×1tan44×1[cot=1tanθandtan45=1]=1×1..........×1=1

Hence, the value of tan1tan2tan3.......tan89is 1.


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