Consider a circuit with a potential difference of 5 V, with a current of 2 A flowing and the internal resistance of the battery at 0.8 ohms. Calculate the EMF in the circuit.
Solution:
The EMF in a circuit can be calculated using the formula:
Substituting the values in the above equation, we get
5 V + 2 A × 0.8 Ω
5 V + 1.6 V = 6.6 V
So the EMF of the circuit is 6.6 V.
