# Calculate the EMF of the given circuit

Consider a circuit with a potential difference of 5 V, with a current of 2 A flowing and the internal resistance of the battery at 0.8 ohms. Calculate the EMF in the circuit.

Solution:
The EMF in a circuit can be calculated using the formula:

$$\varepsilon=V+Ir$$

Substituting the values in the above equation, we get

5 V + 2 A × 0.8 Ω

5 V + 1.6 V = 6.6 V

So the EMF of the circuit is 6.6 V.