Question

Consider a circuit with a potential difference of 5 V, with a current of 2 A flowing and the internal resistance of the battery at 0.8 ohms. Calculate the EMF in the circuit.

Answer 1

Step 1: Given data

The potential difference $V=5V$ , current $I=2A$ , resistance $r=0.8\Omega$

Step 2: Formula used

EMF in a circuit, $\epsilon =V+Ir[whereV=potentialdifference,I=current,andr=resis\tan ce]$

Step 3: Calculating EMF in the circuit

Using the above formula and given data

$$\begin{gathered} \epsilon =5V+2A\times 0.8\Omega \\ \epsilon =5V+1.6V \\ \epsilon =6.6V \end{gathered}$$

Hence, the EMF of the circuit is $6.6V$