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Question

Find the zeroes of the polynomial: p(𝑥)=(𝑥-2)2(𝑥+2)2.


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Solution

Step 1: Form the equation

The given polynomial is p(𝑥)=(𝑥-2)2(𝑥+2)2.

We know that the zeroes of a polynomial are evaluated by equating it with zero.

px=0

(𝑥-2)2(𝑥+2)2=0

Step 2: Solve to find the zeroes

(𝑥-2)2(𝑥+2)2=0

x-2+x+2x-2-x+2=0 a2-b2=a+ba-b

x-2+x+2x-2-x-2=0

2x-4=0

-8x=0

x=0

Hence, the zero of this polynomial is 0.


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