Find three consecutive odd numbers whose sum is 147.

Let the three consecutive numbers be (2x+1), (2x+3) and (2x+5)

we can write 2x + 1 + 2x + 3 + 2x + 5 = 147

On simplifying we get 6x+9=147

On rearranging we get

6x = 147 – 9

6x = 138

x = 138/6 = 23

So the numbers are (2x+1)=47

(2x+3) = 49

(2x+5) = 51