Answer: (3)
We know that:
λ1= R(1/n12−1/n22)
For last line Balmer’s series,
n1=2 and n2=∞
λ1= 107(1/22−1/∞2)
λ1= 0.25×107m−1
Answer: (3)
We know that:
λ1= R(1/n12−1/n22)
For last line Balmer’s series,
n1=2 and n2=∞
λ1= 107(1/22−1/∞2)
λ1= 0.25×107m−1
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